Find the equation of the line that is parallel to the line - 2y+7x=3 passes through the point (1,-3). Can you please show details thank you for your help.

Question

anonymous · Answer

Show the given equation in slope-intercept form y = mx + b.

7/2x -3/2 = y   the slope is the coefficient of x or 7/2

A parallel line will have the same slope of 7/2, which is m in the equation.

Now you can substitute in to the equation using the point given (1, -3)
y = mx + b
-3 = 7/2(1) + b    solve for b
-3 - 7/2 = b
-6.5 = b               you can write b as a fraction, -13/2

So you have: y = 7/2x - 13/2. To put into standard form, multiply everything by 2
2(y = 7/2x - 13/2) = 2y = 7x-13
                                 13 = 7x - 2y  or 7x - 2y = 13

anonymous · Answer

I am horrible a math, can you tell me how you got 7/2x -3/2 = y   the slope is the coefficient of x or 7/2, please. Thank you.

anonymous · Answer

Oh i got it  -2y+7x=3
-2y=3-7x
y=(3-7x)/2

anonymous · Answer

thank you for your help DSS your awesome :)