Question

the mean average temperature of Fairbanks, Alaska, is 27 degrees f. the monthly average temperatures vary between 36.5 degrees above and below this value. If t=0 represents February, the phase shift of the sine function is 2.
a)write a model for the average monthly temperate in Fairbanks, Alaska.
b) according to your model, what is the average temperate in November.
1) a) y=18.3 sin(t/6*3.14+3.14/3)+27
b)y(10)=8.7 degrees
2) a) y=27 sin(t/6*3.14+2(3.14)/3)+36.5
b) y(10)=23 degrees
3) a) y=18.3 sin(t/12*3.14-3.14/6)+27
b) y(9)=44.6 degrees

Answer 1

4) a)y=36.5 sin(t/6*3.14-3.14/3)+27
b) y(9)=8.8 degrees

Answer 2

@agent0smith @razor99 @ranga @phi hey can you guy help me

Answer 3

sin(x) varies from a min value of -1 up to a max value of +1
0 is the mean value.

if you want your sin to vary between 36.5 degrees above and below 27º F, you would want to multiply it by 36.5
(and add a 27)

so without knowing anything else, look for an answer that has
27 + 36.5 sin( stuff)

Answer 4

what do u mean by stuff? @phi

Answer 5

i think it's # 2?? @phi @agent0smith

Answer 6

@Loser66

Answer 7

okay but i thought the amp was the highest point which would be 24+36.5

Answer 8

Amplitude is how far it varies above or below the average.

Answer 9

so it either 1 or 3

Answer 10

i think is 3 actually because November is the 9th month

Answer 11

" average temperature of Fairbanks, Alaska, is 27 degrees f."
this means there needs to be a +27

"the monthly average temperatures vary between 36.5 degrees above and below this value."
this means the amplitude is 36.5, not half of that, since it can be 36 above the mean or 36 below the mean.

So 36.5sin(stuff) + 27

Question seems to be lacking a correct answer.

Answer 12

"average temperatures vary between 36.5 degrees above and below this value. "

Actually I think this means it varies by 36.5 from the max to the min. So amplitude is half that... it's poorly worded.

Answer 13

So 18.25sin(stuff) + 27

Answer 14

i put in # 3 but it was actually number 4 i just summit it :/

Answer 15

thanks for the help tho @agent0smith @phi

Answer 16

lol you probably should've showed #4 as an option...

Answer 17

I didn't even notice it in the second post...

Answer 18

btw screenshots work better than this too... these aren't easy to read.

1) a) y=18.3 sin(t/6*3.14+3.14/3)+27
b)y(10)=8.7 degrees
2) a) y=27 sin(t/6*3.14+2(3.14)/3)+36.5
b) y(10)=23 degrees
3) a) y=18.3 sin(t/12*3.14-3.14/6)+27
b) y(9)=44.6 degrees

Answer 19

i'll do that next next lol thanks agin for the help mane @agent0smith