Question

Which value is an extraneous solution to the equation, |3x+2| = 4x + 5?

-1

-3

-7

10

Answer 1

take out the absolute value bars for now.
3x+2=4x+5

now combine like terms.
4x-3x=1x
=> 2=1x+5

Solve for x.
2-5= -3
=>

-3=1x

x=-3

Answer 2

\(\bf |3x+2| = 4x + 5\implies
\begin{cases}
+(3x+2) = 4x + 5\implies 3x+2 = 4x + 5\\ \quad \\
\bf -(3x+2) = 4x + 5\implies -3x-2=4x+5
\end{cases}\)

what values would you get for "x" from that?

Answer 3

Thanks @calculusxy and @jdoe0001

Answer 4

Ur welcome :)