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Please help! Simplify (16x4y3) ÷ (4x4) A. 4x8y3 B. 4x8 C. x4y3 D. 4y3
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\[\frac{ 16x^4y^3 }{ 4x^4 }\] The x^4's cancel out. 16/4 reduces to 4. You are left with 4y^3
\[16\div 4 =4\] and \[x^4\div x^4=1\]
hey do you know synthetic division? so much easier?
\(\bf \cfrac{ \cancel{16}\cancel{x^4}y^3 }{ \cancel{4}\cancel{x^4} }\implies ?\)
thank you everyone!
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