Question

Simplify the following expression.

sec^2x + sin^2x - tan^2x + cos^2x


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Answer 1

just pythagorean identities
\(\Large \sin^2x+\cos^2x =1 \\ \Large \sec^2x -\tan^2x =1\)

Answer 2

sec^2x + sin^2x - tan^2x + cos^2x

= (sec^2x - tan^2x) + (sin^2x + cos^2x)
=...

Answer 3

@hartnn 2??

Answer 4

absolutely :)