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Check if my answer is correct please! In right triangle ABC, a = square root 3 and b = square root 6. Find sinA. https://media.glynlyon.com/g_trg_2013/1/rt_triangle_abc.gif 1/3 squareroot3/3 squareroot3/squareroot9 squareroot6/3 <<<
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a=sqrt(3), b=sqrt(6), c=sqrt(3+6)=sqrt(9)=3
Sin(A) = opposite/hypotenuse = a / c = sqrt(3)/3
@Agent47 thank you so much!! if you dont mind, could you check out if my answer is correct for two other questions??
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