Question

Check if my answer is correct please!

In right triangle ABC, a = square root 3 and b = square root 6.

Find sinA.

https://media.glynlyon.com/g_trg_2013/1/rt_triangle_abc.gif

1/3
squareroot3/3
squareroot3/squareroot9
squareroot6/3 <<<

Answer 1

a=sqrt(3), b=sqrt(6),
c=sqrt(3+6)=sqrt(9)=3

Answer 2

Sin(A) = opposite/hypotenuse = a / c = sqrt(3)/3

Answer 3

@Agent47 thank you so much!! if you dont mind, could you check out if my answer is correct for two other questions??