Question

Evaluate:

Answer 1

\[\LARGE \int\limits_{0}^{3} 3x^2-4x+1~dx\]

Answer 2

wth??

Answer 3

First we would integrate:
\[\LARGE (x^3-2x^2+x)|_{0}^3\]
Now plug in and solve:
\[\LARGE [(3)^3-2(3)^2+3]-[(0^3)-2(0)^2+0]\]
So:
\[\LARGE 27-18+3\]
\[\LARGE =12\]
Right?

Answer 4

i would say yes

Answer 5

Yay~

Answer 6

@sourwing please dont use language in this website.
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