Question

evaluate the integral
∫ (4dx)/(3+6x)

Answer 1

\[\int \frac{4dx}{3+6x}\]Factorize the denominator, we get \[=\int\frac{4dx}{3(1+2x)}\]Pull out the constant 4/3, we get\[=\frac{4}{3}\int\frac{1}{1+2x}dx\]Do you know how to integrate it now?

Answer 2

no sorry i dont know how

Answer 3

Do you know how to integrate \(\frac{1}{x}\) ?

Answer 4

i think i've got it now 2/3 ln abs (-3-6x) +c

Answer 5

The abs(-3-6x) part does not seem right.

Answer 6

abs(3+6x)