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find the value of sin^-1,0
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say, \(x = \sin^{-1}0 \) take \(\sin\) both sides \(\sin x = \sin~ \sin^{-1} 0\) \(\sin x = 0\) wat value of x makes sinx = 0 ?
is it 0?
thats it, sin 0 = 0 also, sin (pi) = 0
so the answer is 0, pi within the interval [0, 2pi)
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