Question

An isosceles trapezoid has base angles equal to 45 and bases of lengths 6 and 12. Find the area of the trapezoid.

Answer 1

The height of the trapezoid is 3 since the shape is isosceles trapezoid and is 45-45-90 degree triangle, and to find its height, subtract the bases and then divide the answer by 2.

(12-6)/2
6/2=3
Now find the area of a trapezoid
Area = average of bases times height
where b1, b2 are the lengths of each base and h is the height.
Area = (b 1 + 2)/2 x h
Area = (12 + 6)/2 x 3
Area = 9 x 3
Area = 27

Answer 2

@thockenberry14 u there?

Answer 3

yes thanks

Answer 4

i understand it now

Answer 5

Area = (b 1 + 2)/2 x h
i messed up in the area
it should be
Area = (b 1 + b2)/2 x h

No problem ::)

Answer 6

ok