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OpenStudy (anonymous):
Can someone help me? Which answer continues?
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OpenStudy (anonymous):
OpenStudy (anonymous):
The equation that is continuous will not have a number where the denominator equals 0
OpenStudy (anonymous):
A is not correct because 1-1 = 0 B is not correct because 1-1^2 = 0 C is correct because 1+anything^2 is positive, so the denominator will be positive
OpenStudy (anonymous):
Can you help me with another one like this @KirbyLegs?
OpenStudy (anonymous):
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OpenStudy (anonymous):
The answer is B Does that make sense?
OpenStudy (anonymous):
would you mind explaining?
OpenStudy (anonymous):
A is not correct because 1 + 1 = 0 B is correct because 1 + -1 + 1 is not 0, it's 1
OpenStudy (anonymous):
That does make sense! Thank you!
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