Question

Solve this exponential equation: log(3-x)=-1

Answer 1

\[\huge \log_{10}(3-x) = -1\]
\[\huge \text{Use this rule:}\]
\[\huge \log_a x = b ~~~~~ x = a^b\]

Answer 2

\[\large \text{Treat (3-x) as a variable and just use that rule to solve for x}\]

Answer 3

So i shouldn't be expanding the long into the brackets?

Answer 4

log base a times x