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Mathematics
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Two geom. questions
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to find y in the first question \[3\sqrt{2} (\sqrt{2} )\]
then since you know this you could find the side which is x=3
a way to find x is \[3\sqrt{2}\div \sqrt{2}\]
would it be the same way to find y ?
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no because that triangle is a 45 45 90 and in the next problem it is a 30 60 90 triangle
z= \[8\sqrt{3}\] y= \[4\sqrt{3}\] x= \[6\sqrt{2}\] this is for the 2nd question
thanks :)
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