Question

Find all solutions to 2sin(x)cos(x) - sin(x)=0 in the interval [0,2pi), keep answer in radians with pi. Can you also explain to me how you got the answer please

Answer 1

2sin(x)cos(x) - sin(x)=0
sin(2x)-sin(x) =0
sin (2x)=sin (x)
can you go on ?

Answer 2

2sin(x)cos(x) - sin(x)=0


sin(x)(2cos(x) - 1) = 0


sin(x) = 0 or 2cos(x) - 1 = 0


sin(x) = 0 or 2cos(x) = 1


sin(x) = 0 or cos(x) = 1/2


I'll let you finish