Question

Could somebody please check if I am doing this right. sketch the graph y=x^4 -4x^2 + 4

Answer 1

When x=0 , y= 4 so we get point (0,4)

Y= x^4 -4x^2+4 becomes x^2(x^2-4) +4 = 0

Answer 2

So far am I right????

Answer 3

hint : y= (x^2-2)^2

Answer 4

y= (x-sqrt(2)^2(x+sqrt(2))^2