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Mathematics 13 Online
OpenStudy (anonymous):

the points x y is at a distance 5 from p(-2 4) ? what is the answer?

OpenStudy (anonymous):

(3, 9)

OpenStudy (anonymous):

The locus of all points equidistant from a fixed point is a circle of center that point and of radius the common distance from this point.

OpenStudy (anonymous):

Eliassaab is correct, read the page below if you wish to get a better understanding http://www.regentsprep.org/regents/math/algtrig/ATC1/circlelesson.htm

OpenStudy (amoodarya):

|dw:1388843626007:dw|all points equidistant from a fixed point is a circle of center (-2,4) with r=5

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