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Find the product of (x + (3+5i))^2.
first fallow (a+b)^2 formula.... (a+b)^2=a^2+b^2+2ab
then where ever you get i^2 replace with -1
i think you got it....
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@omgkelley
Okay :)
(x + (3+5i))^2 =(x + (3+5i))(x + (3+5i)) =(x^2 + x(3+ 5i) + x(3+ 5i) + (3+ 5i)^2) =(x^2 + x(3+ 5i) + x(3+ 5i) + {(3+ 5i)(3+ 5i)} =(x^2 + x(3+ 5i) + x(3+ 5i) + {9 + 15i + 15i +25(-1)} =(x^2 + x(3+ 5i) + x(3+ 5i) + 9 + 30i - 25) =(x^2 + 2x(3+ 5i) + 9 + 30i - 25) =(x^2 + 6x + 10xi +9 + 30i - 25) =(x^2 + 6x + 40i -16)................Answer
@omgkelley ^ check it
Thank you soooooo much! :D :D
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