Question

The curve cuts the y axis at (0,2) and the x axis at (-1,0),(1,0) and (2,0) What is the equation of the curve?

Answer 1

basically you're give 3 zeroes/roots of the polynomial
and the value at 0

Answer 2

do u knw how to write a polynomial wid zeroes of -1, 1, 2 ?

Answer 3

No don't think so haha

Answer 4

\[(x-1)(x+1)(x-2)=f(x)\]

Answer 5

if k is a zero of polynomial,
then (x-k) is a factor

Answer 6

Still don't get it

Answer 7

if you have a factored polynomial with factor (x-a), then a is one of the zeros. Now you're just reversing the process.

Answer 8

since \(-1, 1, 2\) are zeroes,
\((x--1), (x-1), (x-2)\) will be factors.

so the polynomial can be represented as :-
\(f(x) = k(x+1)(x-1)(x-2)\)

you need to find \(k\) and plugin above

Answer 9

The question as asked has many solutions. The question should specify that the function is a polynomial.