Question

a)factorize 8p^3-27^q3
b) hence, factorize 8p^3+12p^2q-18pq^2-27q^3

Answer 1

For (a) I would use the difference of cube i.e. a^3-b^3=(a-b)(a^2+ab+b^2)

Answer 2

For (b), I would factorize the rest except 8p^3 and -27q^3. They will have a common factor.

Answer 3

a) (2p-3q)(4p^2+6pq+3q^2) right

Answer 4

nope

Answer 5

=,=k i'll try again

Answer 6

oops typo *9

Answer 7

exactly, but you've deleted your comment already xP