Question

calculate 2 iterations of newtons method to approximate a zero of the function f(x)=x^3+x+1 in the interval [-1,0]. Round to 4 decimal places after each interation.

Answer 1

use the iterative formula

x1 = x0 - f(x0)
----
f'(x0)

Answer 2

Do you think you can just show me how to do it?

Answer 3

first can you find f'(x)?

Answer 4

can u find derivative of x^3 + x + 1?

Answer 5

yes 3x^2

Answer 6

well almost right
its 3x^2 + 1