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OpenStudy (anonymous):
If y=x^3/x^2+1, then y′(2√)=
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OpenStudy (anonymous):
What is y'?
OpenStudy (anonymous):
2 square root of what?y′(2√)
OpenStudy (anonymous):
sorry its y'(√2)
OpenStudy (loser66):
first off, y =?
OpenStudy (anonymous):
y=x^3/x^2+1
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OpenStudy (loser66):
ok, if you cannot simplify it, let it there and take derivative, y' =?
OpenStudy (anonymous):
gotcha
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