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Prove sinx^2= 1-cos2x/2, use the left side to start the proof.....help please?
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\[\sin x^2=1-\frac{\cos (2x)}{2}\]
Is that what you meant to post?
wait instead of sinx^2 its actually sin^2x sorry my bad
\[\sin ^2x=1-\frac{\cos 2x}{2}\]
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it looks like this: |dw:1388979679581:dw|
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