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Mathematics 24 Online
OpenStudy (anonymous):

solve by using the elimination method: -2x+2y+3z=0 -2x-y+z=-3 2x+3y+3z=5 solve by substitution: -z-y-z=-8 -4x+4y+5z=7 2x+2z=4 please show all steps thanks!

OpenStudy (anonymous):

let's see

OpenStudy (anonymous):

thanks!

OpenStudy (anonymous):

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