The sum of two consecutive odd integers is 68. hat is the smaller number?

Question

ganeshie8 · Answer

try 31+33
try 33+35
try 35+37

kc_kennylau · Answer

Let the smaller integer be n, and the larger integer be n+2.

kc_kennylau · Answer

How to express your question in equation?

ganeshie8 · Answer

or express it as equation and do it in royal way ;)

anonymous · Answer

here are the answers i have to choose from A.29 B. 31 C. 33 D.35

wolf1728 · Answer

An odd integer is expressed as 2x + 1
So the 2 consecutive odd integers are 
2x +1 and 2x +3
2x +1 + 2x + 3 = 68
4x + 4 = 68
4x = 64
x = 16
2x +1 = 33 
2 x + 3 = 35
Smaller number is 33

anonymous · Answer

(2x+1)+(2x+3)=68
4x+4=68
4x=64
x=16
therefore smaller number= 2x+1
                                      =2(16)+1
                                       =33

anonymous · Answer

lol did working then u posted urs first

kc_kennylau · Answer

Let the smaller integer be n, and the larger integer be n+2.
n+(n+2)=68
2n+2=68
2n=66
n=33

Therefore the smaller integer is 33.

kc_kennylau · Answer

So much simpler :P

wolf1728 · Answer

well great minds think alike !!

kc_kennylau · Answer

nope  my mind ain't great great is your mind :)

wolf1728 · Answer

Sounds a bit like Yoda

kc_kennylau · Answer

yoda goes like this "great, your mind is" xD