Question

hi :) can you help me guys to answer this one? thanks :*

'how to divide polynomial using synthetic division in degree 2?'

Answer 1

\[\frac{x^2+2x-8}{x-2}:\]
\[\begin{array}{c|ccc}
&1&2&-8\\
2&\downarrow&2&8\\\hline
&1&4&0
\end{array}\]
Ignore the 0 at the end, the quotient is x+4.

Therefore x^2+2x-8=(x-2)(x+4)

Answer 2

i mean, the factor of the polynomial is a quadratic