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Mathematics 11 Online
OpenStudy (anonymous):

C=x^2+y^2-z^2/2xy medals will be given

OpenStudy (perl):

whats the question?

OpenStudy (anonymous):

C=\[x^2\]+\[y^2\]-\[z^2\]\[\div 2xy\]

OpenStudy (anonymous):

making z as a subject

OpenStudy (anonymous):

we know that but what are we solving for? x y z? or just factoring?

OpenStudy (perl):

making z as the subject of what? please speak english

OpenStudy (anonymous):

can you understand my question i have given the equation in that we have to make z as a subject of the formula

OpenStudy (anonymous):

\[z=\sqrt{x^2+y^2-2cxy}\]

OpenStudy (anonymous):

whole solution please

OpenStudy (anonymous):

\[\sqrt{-x^2+y^2−2cxy}\]

OpenStudy (anonymous):

that's your other half

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