Question

Can someone please help me find the x-intercepts and vertex of f(x)=x^2-7 and sketch a graph?

Answer 1

for intercepts:
it is clear for y it is -7
for x take y=0 then x^2=7 x=\[\sqrt{7}\] or x=\[-\sqrt{7}\]

Answer 2

i only need to find the x-intercepts, so the x-intercepts would actually just be √7 and -√7??

Answer 3

yes exactly

Answer 4

so I wouldnt factor the x^2 and 7 so that it is x(x-7) x=0 x=7?

Answer 5

just look carefully x(x-7) is x^2-7x bu its equation is x^2-7 not -7x

Answer 6

oh! so the vertex is (0,-7)?