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given sin beta=6/11 and sec beta>0, find cos beta and tan beta.
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\(sin \beta = \dfrac{y}{c} \)
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For the right triangle with legs x and 6, and hypotenuse 11, can you find the value of x?
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sec is positive in QI and QIV
so then i do a^2+b^2=c^2??
sin is positive in QI and QII so only examine Q1
yes
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x=sqart85 @mathstudent55
Correct. Now you can get cos beta and tan beta.
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