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Mathematics 18 Online
OpenStudy (anonymous):

solve for x e^x e^(x+1)=1

OpenStudy (amoodarya):

|dw:1389046508871:dw|is it ?

OpenStudy (anonymous):

yes

OpenStudy (amoodarya):

|dw:1389046539112:dw|so 2x+1=0

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