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How do i find H, Need to know the equation.
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not too hard... start at the top and call the left top angle inside the triangle theta. \[27 cos\theta = 24\] \[cos\theta = \frac{24}{27}\] \[theta = cos^{-1}(\frac{24}{27})\] \[theta = 27.27\]
then find the other angle we'll call it alpha \[\alpha=90 - 27.27 = 62.73\] alpha is the same angle as the bottom left, and also the same as the one in the outside of the parallelogram in the triangle with h
\[h = 36sin\alpha\]
don't round the numbers like I did, cause it will come out even if you don't \[h = 32^{\circ}\]
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