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write sin(2arccos(x/3)) as an algebraic expression
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first, use the double angle formula sin(2x) = 2 sin(x)cos(x)
so, sin(2arccos(x/3)) = 2 sin(arc cos(x/3)) cos(arccos(x/3))
http://www.algebra.com/algebra/homework/Trigonometry-basics.faq.question.247773.html
That should help you ;)
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@RadEn then how do I make the triangle?
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