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Mathematics
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OpenStudy (iesmee):
Solve each equation by factoring
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OpenStudy (iesmee):
\[3v^{2}+8v+10=5\]
OpenStudy (iesmee):
\[5x ^{2}+26x+2=-3\]
OpenStudy (usukidoll):
I would find the discriminant first and then use quadratics if its necessary
OpenStudy (anonymous):
3v^2 + 8v + 10 - 5 = 0
3v^ + 8v + 5 = 0
(v+1)(3v+5)
v = -1 or -5/3
OpenStudy (anonymous):
5x^2+26x+2=−3
5x^2+26x+2+3 = 0
5x^2+26x+5 = 0
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OpenStudy (anonymous):
(5x+ )(x + ) You're going to use a 3 & 1...you must decide where to place them in the parenthesis
OpenStudy (iesmee):
Do I kick it to the back..? not sure how this is donw
OpenStudy (iesmee):
@Directrix
OpenStudy (anonymous):
sorry...I got kicked off the internet...it's 5 & 1 not 3 & 1
OpenStudy (anonymous):
(5x+ 5 )(x + 1 )= 5x^2+10x + 5 not right...doesn't lead to original question
(5x+ 1 )(x + 5 )= 5x^2 + 26x + 5 this works so the parenthesis are right
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OpenStudy (anonymous):
x = -1/5 or -5
OpenStudy (iesmee):
both answers are correct and the steps are above
OpenStudy (iesmee):
i see, thank you very much
OpenStudy (anonymous):
you're welcome
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