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Mathematics 19 Online
OpenStudy (anonymous):

Find the area of each triangle: Picture below:

OpenStudy (anonymous):

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OpenStudy (anonymous):

Using laws of sin and cos

OpenStudy (anonymous):

\[\huge c^2 = a^2 + b^2 - 2ab \cos(C)\]plug in the points and solve

OpenStudy (anonymous):

is the c with the 8.4 correct?

OpenStudy (anonymous):

\[\huge c^2 = 8.5^2+12^2- 2*8.5*12\cos(21)\]

OpenStudy (anonymous):

^^^ that is to find the c

OpenStudy (anonymous):

So the formula is 1/2absinC?

OpenStudy (anonymous):

I plugged that in and got 327.98. The square root would be 18.1?

OpenStudy (anonymous):

Wait my formula of area of tris says: 1/2absinC >>> Wouldn't the formula just be 1/2x12x8.5xsin21 ?

OpenStudy (anonymous):

c^2 = 216.25-204*0.83358 c^2 = 25.7995 c = 5.079

OpenStudy (anonymous):

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