Find the area of the triangle. image of a triangle in which two sides are labeled 9 point 5 in and the third side 10 point 2 in; a dashed line originates in the corner formed by the two 9 point 5 in sides and extends to the 10 point 2 in side; a box is in the right corner where the dashed line intersects the 10 point 2 in side 48.45 in2 20.4 in2 40.8 in2 81.6 in2
Area = 1/2bh, where b is base and h is height. B and h must be at a right angle to each other.
Any ideas using this formula?
no idea at all
If you use the side that is 10.2 in long, then the height could be the dotted line.
So, Area=1/2*10.2*8 in^2
The box between that side and the doted line means the lines are at right anglesto each other.
*angles to
Can you calculate it now?
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