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Solve algebraically for all values of x: x^4+4x^3+4x^2=-16x
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add 16x to the other side, then solve by setting it equal to 0
i did that and i kept going but i got confuse ):
confused
did you factor out the x?
i factored by grouping
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then you should know one answer is 0
and i got (x^3+4)(
one answer is x=0
*(xplus4)
yea i know that and i got -4
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thats it! good job!
but idk how to get the third solution
x=0, and -4
lol xD but the answer key also has...
+- 2i,
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oh. well do you know the quadrilateral formula?
yes! but idk where i use it ! my work may be wrong i'm afraid l:
i don't have a trinomial
oh
|dw:1389070182109:dw|
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