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Mathematics 8 Online
OpenStudy (ammarah):

Evaluate the logarithm without using a calculator.

OpenStudy (ammarah):

|dw:1389081315580:dw|

random231 (random231):

do hav any idea?

OpenStudy (kc_kennylau):

\[\Large\log_3\frac13=\log_33^{-1}=\cdots\]

random231 (random231):

yeah thats it.

OpenStudy (ammarah):

what after that?

random231 (random231):

property of log::: loga^n=nloga

OpenStudy (kc_kennylau):

property of log: log_n n^x = x (This is the definition of log :P)

OpenStudy (kc_kennylau):

PostScript: "log_n" means logarithm base n

OpenStudy (ammarah):

so it would be 3^-1=3?

random231 (random231):

hey i was giving a generalised def @kc_kennylau

OpenStudy (kc_kennylau):

@random231 yours was not a def xD

OpenStudy (kc_kennylau):

that's a property/formula xD

OpenStudy (ammarah):

??? heloo is my answer correcttt

OpenStudy (kc_kennylau):

3^-1 is not 3

OpenStudy (kc_kennylau):

3^-1 is 1/3

OpenStudy (ammarah):

wait so whats my final answer ..

random231 (random231):

-1

random231 (random231):

isnt it @kc_kennylau

OpenStudy (kc_kennylau):

yes

OpenStudy (ammarah):

can u guys please draw out the steps for me>

OpenStudy (kc_kennylau):

\[\Large\log_3\frac13=\log_33^{-1}=-1\]

OpenStudy (anonymous):

|dw:1389081700035:dw|

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