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The equation of line LM is y = 5x + 4. Write an equation of a line perpendicular to line LM in slope-intercept form that contains point (-3, 2).
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Select one: a. y = -5x + 13 b. y= -1/5x + 7/5 c. y= 1/5x - 7/5 d. y= 5x-17
nurali can you help me please on some questions
y=5x+4 The slope of this line is 5. The slope of a perpendicular line is the negative reciprical: -1/5 Now use the point-slope formula to find the equation: y - y1 = m (x - x1) y - 2 = -1/5 (x + 3) y-2 = -1/5x - 3/5 y = -1/5x-3/5+2 y = -1/5x+7/5
so y = -1/5x+7/5 is the answer
Yes
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thank you
My Pleasure.
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