The equation of line LM is y = 5x + 4. Write an equation of a line perpendicular to line LM in slope-intercept form that contains point (-3, 2).

Question

anonymous · Answer

Select one:
a. y = -5x + 13 
b. y= -1/5x + 7/5 
c. y= 1/5x - 7/5 
d. y= 5x-17

anonymous · Answer

nurali can you help me please on some questions

nurali · Answer

y=5x+4

The slope of this line is 5. The slope of a perpendicular line is the negative reciprical: -1/5 

Now use the point-slope formula to find the equation: 
y - y1 = m (x - x1) 
y - 2 = -1/5 (x + 3) 
y-2 = -1/5x - 3/5 
y = -1/5x-3/5+2 
y = -1/5x+7/5

anonymous · Answer

so y = -1/5x+7/5
is the answer

nurali · Answer

Yes

anonymous · Answer

thank you

nurali · Answer

My Pleasure.