Question

Write a program to find the “sum of the squares” of the numbers from 1 to 100 ,e,g,1*1 + 2*2 + 3*3 +…+ 100*100.

Answer 1

writing code java

Answer 2

int count=0;
for(int i=1; i<=100; i++){
count+=i^2;
}
System.out.println(count);

//P.S. not tested

Answer 3

are you sure?

Answer 4

test it for yourself?

Answer 5

yes it's correct.thank you so much!

Answer 6

no problem :)

Answer 7

oh! i have one more exercise.

Answer 8

Write a program to display multiplication table from two to nine for example:
2 x 1 = 2 …….. 2 x 2 = 4 2 x 3 = 6 2 x 4 = 8 2 x 5 = 10 2 x 6 = 12 2 x 7 = 14 2 x 8 = 16 2 x 9 = 18 2 x 10 = 20

Answer 9

Hint: for loop from i=1 to i<=10 :)

Answer 10

for(int i=0;i<=10;i++){
System.out.println("2×"+i+"="+2*i);
}

Answer 11

ok.i will test it.

Answer 12

what about this:
Write a program to sum only the odd number from 1 to 100.

Answer 13

Do I have to do everything for you xP

Answer 14

Hint: Odd numbers can be expressed in the form 2n+1

Answer 15

yes

Answer 16

I won't do this this time, tell me your attempt and I try to correct it

Answer 17

because this exercise i can't do it.i try again and again.but i not sure about this exercise!

Answer 18

Tell me what's in your mind :)

Answer 19

about this exercise?

Answer 20

yes :)

Answer 21

i think should be have a condition to notice odd number!

Answer 22

Hint: run i from 0 to 49, and make i odd by 2*i+1 :)

Answer 23

how to sum it?

Answer 24

declare a variable called count outside the for loop :)

Answer 25

i'm not clear about for loop.can you write it to me?

Answer 26

int count=_;
for int(i=_;i<=__;i__){
count+=2*i+1;
}

Fill in the blanks :D

Answer 27

i=0;i<=100;i++

Answer 28

no, you wanna add the odd numbers from 1 to 99

For what value of i will 2*i+1 produce 1?
For what value of i will 2*i+1 produce 99?

Answer 29

For value of i will 2*i+1 produce 99.

Answer 30

huh?!

Answer 31

int count=0;
for int(i=0;i<=49;i++){
count+=2*i+1;
}
System.out.println(count);

Answer 32

all odd number from 1 to 100 not 1 to 50

Answer 33

2*i+1 gives you the odd numbers

Answer 34

so it will be(i=1;i<=99;i++)

Answer 35

\[\begin{array}{c|c}
i&0&1&2&3&4&5&6&7&8&9&10\\\hline
2i+1&1&3&5&7&9&11&13&15&17&19&21
\end{array}\]

Answer 36

I'm not adding i to the count each time.

Answer 37

I'm adding 2*i+1 to the count each time.

Answer 38

yes this i understand!

Answer 39

:)

Answer 40

2i+1 is from 0 to 99

Answer 41

i mean 1 to 99

Answer 42

then i is from 0 to 49 :)

Answer 43

i from 1 to 100

Answer 44

what?

Answer 45

I'm adding the odd integers from 1 to 100 together

Answer 46

But I don't use i to denote the integers

Answer 47

yes i understand!

Answer 48

I use 2i+1 to let it run through the odd integers

Answer 49

Therefore i is from 0 to 49

Answer 50

So that 2i+1 will run through all the odd integers from 1 to 100

Answer 51

Then I add all 2i+1 to the count

Answer 52

yes

Answer 53

Therefore i is from 0 to 49

Answer 54

ok.i understand it all

Answer 55

i will test it now

Answer 56

yay :)

Answer 57

\[100(101)(201)/6\]