Perimeter and area of a rhombus??? Please help!!! http://tinypic.com/r/x40yaa/5 So, I know the parallelogram is a rhombus, but I don't understand how to find the perimeter and area of it. Can someone please help me?
do you know distance formula ?
you can find distance AB since you have the co-ordinates of A and B
Distance between points (x1,y1) and (x2,y2) is \(\huge d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\)
So...The distance between them is...5.38, right?
YES :) and BC = ...?
Is the same thing? 5.38?
oh, oops , yes, you said its rhombus then whats AD =CD = ... ?
Uh...I'm not sure...how do you find that?
a rhombus has all sides equal, all are 5.38 . ok, so perimeter = 4* 5.38
Ahh, okay, so then the perimeter is 21.52 then. What about the area?
find the lengths of diagonals AC = BD = then area = AC*BD /2
how do I find the lengths of the diagonals?
you have the co-ordinates of A and C use the distance formula to find AC
Okay, give me a sec...
would it be 4.24?
YES! you can keep it as 3 \(\sqrt 2\) BD = ... ?
would it be 9.89?
YES! you can keep it as 7\(\sqrt 2\) now find the area
area = AC*BD /2
So then, the area is 20.9668 units?
to be accurate its 21 :)
Ah, okay! Thanks sooooooooooo much for the help! I really needed it. And, I learned something new! :D
i'm glad to hear that! :) you're most welcome ^_^
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