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Mathematics 17 Online
OpenStudy (anonymous):

i will give medal

OpenStudy (anonymous):

hartnn (hartnn):

can you find the slope of given line ?

OpenStudy (anonymous):

i don't know how

hartnn (hartnn):

compare it with (y-y1) = m (x-x1) then m= slope

hartnn (hartnn):

so the slope of your line will be m'=1/3 slope of perpendicular line = -1/m' = -1/ (1/3) = -3

hartnn (hartnn):

now we have point (-4,3) and slope m = -3 use this equation, y-y1 = m (x-x1) x1 = -4 y1 = 3

OpenStudy (anonymous):

what do i do with the other side there is no numbers

OpenStudy (anonymous):

m = -3 x1 = -4/y1 = 3

hartnn (hartnn):

y - 3 = (-3) (x+4) simplify

OpenStudy (anonymous):

y = 3?

hartnn (hartnn):

where did the x go ? :O

hartnn (hartnn):

y - 3 = (-3) (x+4) y-3 = -3x -12 y =-3x -12 +3 y = -3x -9

OpenStudy (anonymous):

oh

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