Can u guys help me with this question? Given two rectangles, one with length = l and width = w, and the second rectangle with length = 2l and width = 4w. How much larger will the perimeter of the second rectangle be than the perimeter of the first rectangle?

P2 = P1 + 4w

P2 = 2P1 + w

P2 = 2P1 + 4w

P2 = P1 + w

Question

Can u guys help me with this question? Given two rectangles, one with length = l and width = w, and the second rectangle with length = 2l and width = 4w. How much larger will the perimeter of the second rectangle be than the perimeter of the first rectangle?

    P2 = P1 + 4w

    P2 = 2P1 + w

    P2 = 2P1 + 4w

    P2 = P1 + w

anonymous · Answer

perimeter = 2*(l+w) for rectangle where l is length and w is width