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Physics 16 Online
OpenStudy (anonymous):

can someone help me ?!?!?!

OpenStudy (anonymous):

\[KE = \frac12 m v^2\] What happens to KE when v increases?

OpenStudy (anonymous):

a?

OpenStudy (anonymous):

Yep. It even looks like a quadratic curve, so it's probably constant acceleration.

OpenStudy (anonymous):

okay thnk you teehee(:

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