Question

I GIVE MEDALS.

You launch a water balloon from the ground with a speed of 8.3 m/s at an angle of 27°.
What is the horizontal component of the velocity?

Answer 1

Just work out the length of the adjacent side of this triangle:



Remember
\[\sin\theta=\frac{opposite}{hypotenuse}\]

\[\cos\theta=\frac{adjacent}{hypotenuse}\]

\[\tan\theta=\frac{opposite}{adjacent}\]

Answer 2

Do you understand? @abbyisaprincess

Answer 3

Finish up with your calculator.