Question

I want to confirm something about factoring quadratics? Thanks. I need to write an equation for this, so if you don't see my reply yet, please excuse me....

Answer 1

okie dokie

Answer 2

\[ax ^{2}+bx+c=(factor of "a"_{1}(x) + factor of "c"_{1})(factor of "a"_{2}(x) + factor of "c"_{2})\] where \[(factor of "a"_{1})(factor of "c"_{2}) + (factor of "a"_{2})(factor of "c"_{1})=b\] is my formula for factoring quadratics into binomials but I want some approval from other people. I tried using it with a few quadratics and it works, although if you have all positive terms you end up needing complex numbers but yea thanks

Answer 3

a little of the first one is cut off the end is \[+ factor of "c"_{2})\]

Answer 4

@derk765

Answer 5

@jdoe0001

Answer 6

looks right

Answer 7

sorta like the reverse FOIL, yes

Answer 8

thanks :D

Answer 9

yw