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the length of a picture frame is 3 in. greater than the width. The perimeter is less than 52 in.
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ok so because it is 3 in greater, the length, l is equal to 3+w so the equation for perimteer is 2l + 2w=p, but you can subsitute for l so \[2(w+3) +2w = p \] so you distribute and get \[2w+6+2w = p\] combine like terms\[4w +6 = 52\] (52 is p) then solve \[4w= 46 \]\[w= 11.5\] and since l is w+ 3, \[l = 14.5\]
I'm assuming you were looking for the length and width?
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