Question

WHat is the value of x? multiple choice

Answer 1

\[x-12\sqrt{x}+36=0\]

Answer 2

A.6 B.6^2 C.6^3 D. 6^4

Answer 3

@ehuman

Answer 4

Hint: \(\large x-12\sqrt{x}+36=(\sqrt{x}-6)^2\). So \(\large (\sqrt{x}-6)^2=0\implies\ldots\)

Can you take things from here? :-)

Answer 5

B?