Question

Solve each system of equations using substitution.

x – y = 1
x = 1/2y + 2
Select one:
(2, 2)
(3, 0)
(3, 2)
(0, 2)

Answer 1

put x=1/2y+2 in first equation
simplify
you will have value of y
so find x

Answer 2

ok

Answer 3

x = 1/2y + 2
x – y = 1 ----> (1/2y + 2)-y=1
multiply by 2

Answer 4

lets solve it together

Answer 5

wait what?

Answer 6

Ok

Answer 7

y=?

Answer 8

Y =
idk :( thats really confusing

Answer 9

ok
again
put x = 1/2y + 2 into x – y = 1
so you have
(1/2y+2) – y = 1
ok ?

Answer 10

ok

Answer 11

now solve for y
(1/2y+2) – y = 1
1/2y+2-y=1
1/2 y-y=1-2

1/2y-2/2y=-1
ok ?

Answer 12

ok

Answer 13

-1/2 y=-1
so multiply by _2
y=+2
ok ?

Answer 14

ok

Answer 15

now we find x
before x = (1/2y+2)
so (y=2)
x=1/2(2)+2
x=1+2
x=3
ok ?

Answer 16

ok so (3,2)

Answer 17

Yay! Can i show u one more

Answer 18

yes

Answer 19

y = x – 2
y = 1/2x + 4
Select one:
(12, 5)
(3, 5)
(12, 10)
(6, 10)

Answer 20

put y = x – 2
into second equation
and write here please

Answer 21

y = x-2

Answer 22

is it 12, 10

Answer 23

from 1st we have
y = x – 2

x-2=y = 1/2x + 4
*2 to be easier
2x-4=x+8

2x-x=4+8
x=12
you are right

Answer 24

Yay thanks :)

Answer 25

your welcome