Question

Help with negative exponents?

4. What is the value of 2x*-2y*-2 for x = 3 and y = -2?
a. 1/18
b. 72
c. 2(-6)*-4
d. 1/648

Answer 1

your question is \[2x ^{-2}*y ^{-2}\]

Answer 2

yeah exactly. sorry, i wasn't sure how to write it out here.

Answer 3

\[=\frac{ 2 }{ x ^{2}y ^{2} }=\frac{ 2 }{ \left( x*y \right)^{2} }=\frac{ 2 }{\left( 3*-2 \right)^{2} }=\frac{ 2 }{ 36 }=\frac{ 1 }{ 18 }\]

Answer 4

thank you! it makes sense now.

Answer 5

yw