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Mathematics 19 Online
OpenStudy (anonymous):

find measure of arc SE

OpenStudy (anonymous):

OpenStudy (mertsj):

Note that chord HG is congruent to chord SE because they are equidistant from the center. Does that help?

OpenStudy (anonymous):

and how do i go on from there

OpenStudy (anonymous):

how would i find the radius of this

OpenStudy (anonymous):

would it be 100

OpenStudy (mertsj):

\[\tan 40=\frac{6}{\frac{1}{2}HG}\]

OpenStudy (anonymous):

but i dont know the measure of HG

OpenStudy (mertsj):

That is exactly the point. Solve that equation for HG

OpenStudy (anonymous):

i got measure of arc se is 100 is that correct

OpenStudy (mertsj):

\[\frac{1}{2}HG \tan 40=6\] \[HG \tan 40=12\] \[HG=\frac{12}{\tan 40}\]

OpenStudy (mertsj):

\[HG=\frac{12}{.839}=14.3\]

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