Question

Factor the following Polynomials.

25z^2-1

4c^2-121

9a^2-100
I'm not sure how to do this at all. I probably have an idea but I'm bot sure what it means or how to do it.

Answer 1

Help please!!

Answer 2

use quadratic formula

Answer 3

all questions above can be factored by using difference square formula :

a^2 - b^2 = (a-b)(a+b)

Answer 4

so like #1 (25-1)(25+1)??

Answer 5

(5z−1)(5z+1)

Answer 6

did you square root 25?

Answer 7

yes.

Answer 8

25z^2-1 = (5z)^2 - 1^2 = (5z - 1)(5z + 1)

Answer 9

ok sweet i think I got it. so would the 4c^2-121 be (2c+11)(2c-11)

Answer 10

Yes you did it right.

Answer 11

2A^4-18a^2?

Answer 12

2A^4-18a^2 = 2 (A^4 - 9a^2)
= 2 ( (A^2)^2 - (3a)^2) )
= 2 (A^2 + 3a)(A^2 - 3a)

Answer 13

2a^2(a-3)(a+3)

Answer 14

i assumed that "A" different with "a"

Answer 15

so, just 2 (A^2 + 3a)(A^2 - 3a)

Answer 16

Ohh lol i didn't notice.
Your totally right. (:

Answer 17

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